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Re: Hydrogen peroxide and reeds

Author: Henry
Date: 2003-04-29 21:34

Yes, but JMcA's treatise contains some rather confusing statements which may be the responsibility not of JMcA but of the author of the quoted text.

1. "Every H2O2 molecule is inherently unstable because it consists of two ions with the same electrical charge (negatively charged HO- hydroxide ions)."
If this were true, H2O2 would have a double negative charge, whereas in reality it is a neutral molecule. I would say that you could think of H2O2 as consisting of two neutral HO "radicals", indicated by HO*. The first step would then be a disintegration of the molecule into two neutral HO* free radicals. (Free radicals are electrically neutral groups with an "unpaired" electron, indicated by a dot. Free radicals are extremely reactive and have been implicated in carcinogenesis.)
2. "The O-- ion is electrically repelled by and thus does not
attach to any other free O-- ion to form an oxygen molecule, so it leaves the liquid solution as gaseous nascent oxygen."
How can the doubly negatively charged O-- escape as neutral, molecular O2, if there are no other redox reactions going on? I have not looked in detail into all the reaction mechanisms involved but what I read here is obviously too simple.

Henry

Post Edited (2003-04-30 02:45)

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