Klarinet Archive - Posting 000271.txt from 2008/01

From: Paolo Leva <paolo.leva@-----.se>
Subj: Re: [kl] 8 #'s?
Date: Wed, 23 Jan 2008 05:32:40 -0500

The number of accidentals of one keys plus the accidentals =0Aof its enharm=
onic key is always 12.=0A=0ALet's take an extreme example: the key of C maj=
or has 0 =0Aaccidentals, so its enharmonic key B# major would have =0A12 sh=
arps. One sharp on B and on E, double sharps on the =0Aother 5 tones. You c=
ould even theoretically write the other =0Aenharmonic key of C major, namel=
y Dbb major (D with two =0Aflats) with 12 flats!=0A=0AThis implies that san=
e persons should never use more =0Athan 6 accidentals, since if you use 7 o=
r more accidentals =0Ayou can always use the enharmonic key and have 5 or =
=0Aless accidentals and make life easier for the musicians.=0A=0APaolo=0Aht=
tp://firstclarinet.blogspot.com=0A=0A> Try this idea: the relative minor of=
B Major is G# minor. The =0A> parallel Major of G# minor is G# Major. A=
s has been said before, the =0A> key signature would be the 7 sharps plus =
(going by the circle of =0A> fifths) the additional F# which would then gi=
ve an F double sharp and =0A> the key of G# Major. Theoretically one coul=
d go further and have =0Aenharmonic equivalents of all the flat keys. G# =
Major is the =0Aenharmonic equivalent of Ab Major.=0ASimeon=0AOn Jan 22, 2=
008, at 10:28 PM, Peter Stoll wrote:=0A=0A> This is confounding me; I count=
only 7 available letter-names for =0A> notes, from A-G (not counting the =
German H)... so how can there be =0A> 8?!? Very interesting thread...=0A=
etic.yahoo.net/index.php?mtcmk=3D148757

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